Why am I not getting a vector output?

2 views (last 30 days)
Hi All,
Ive writen this function that computes the gradient vector for a function, but it only gives me a single value output. What am I doing wrong?
gradlandscape(3, 3);
function [retx, rety] = gradlandscape(x, y)
h = 0.1;
retx = (landscape(x+h, y)-landscape(x-h, y))/(2*h);
rety = (landscape(x, y+h)-landscape(x, y-h))/(2*h);
function M = landscape(x, y)
M = H1(x, y) + H2(x, y);
function h1 = H1(x, y)
R1 = 2;
s1 = [-2;2];
n1 = 2;
h1 = (1./(1+(R1./sqrt((x-s1(1)).^2+(y(:)-s1(2)).^2)).^n1));
end
function h2 = H2(x, y)
R2 = 1;
s2 = [3;-1];
n2 = 1;
h2 = (1./(1+(R2./sqrt((x-s2(1)).^2+(y(:)-s2(2)).^2)).^n2));
end
end
end

Accepted Answer

Adam Danz
Adam Danz on 17 Oct 2019
Edited: Adam Danz on 17 Oct 2019
That's because you're only asking for a single output (by default). If you want both outputs, you must include two outputs in your call to the function.
[retx, rety] = gradlandscape(3, 3)
If the intention of the function was to produce a single output that is a 1 x 2 vector instead of two scalar outputs, then you'll need to change the function like this:
function retxy = gradlandscape(x, y)
h = 0.1;
retxy(1) = (landscape(x+h, y)-landscape(x-h, y))/(2*h);
retxy(2) = (landscape(x, y+h)-landscape(x, y-h))/(2*h);
.
.
.

More Answers (0)

Categories

Find more on Statistics and Machine Learning Toolbox in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!