Convert transfer function to state-space models
10 views (last 30 days)
Show older comments
Diego Garcia
on 11 Oct 2019
Answered: Diego Garcia
on 17 Oct 2019
I'm trying to convert a transfer function to state space model. In order to avoid the control toolbox functions since I don't have it's license.
The transfer function that I'm using is quite simple. Is the model for a heatsink temperature.
For this transfer function I have the next values for A,B,C and D.
I've tried to compare the output from the lsim() function and the equations from above but the output differs

Here's the code that I've used
P = rand(1,10)*1000;
t = 0:1:length(P)-1;
A = -400;
B = 0.5;
C = 0.6658;
D = 0;
%%%%%%%%%%%%%%%%%%%%%%%%%
%%% State space %%%
%%%%%%%%%%%%%%%%%%%%%%%%%
state_space_sys = ss(A,B,C,D);
state_space = lsim(state_space_sys,P,t);
figure
plot(t,state_space)
grid on,grid minor, title('State space')
%%%%%%%%%%%%%%%%%%%%%%%%%
%%% My function %%%
%%%%%%%%%%%%%%%%%%%%%%%%%
x(1:length(P)) = 0;
y(1:length(P)) = 0;
u = P;
for k = 1:length(u)
x(k+1) = A*x(k) + B*u(k);
y(k) = C*x(k) + D*u(k);
end
figure
plot(t,y)
grid on,grid minor, title('My function')
Is there any mistakes on the approach?
It should be quite simple, but I can't manage to find the solution.
7 Comments
Walter Roberson
on 16 Oct 2019
Edited: Walter Roberson
on 16 Oct 2019
Is there a reason not to use tf() and ss() ? That is, if you pass a tf into ss() then it will be converted.
Accepted Answer
More Answers (0)
See Also
Categories
Find more on Time and Frequency Domain Analysis in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
