How do I go about plotting the following function?

1 view (last 30 days)
SF
SF on 9 Oct 2019
Edited: John Doe on 10 Oct 2019
The function I want to plot is x[n] = \delta[n] - \delta[n-a] where a is just a number.
I tried following this tutorial, but I always ended up with out of memory errors.
I know about plotting the impulse function on it's own but this doesn't make any sense to me.
Any and all help is appreciated.

Answers (1)

John Doe
John Doe on 9 Oct 2019
Edited: John Doe on 10 Oct 2019
I've used random numbers.
a = 5
n = [1:1:50]';
delta = 10;
x(n,1) = delta - (delta*(n-a))
plot(x,n)
Alternatively, you could leave n as it is without transposing and plot per the below:
a = 5
n = 1:1:50;
delta = 10;
x(n,1) = delta - (delta*(n-a))
plot(x(:,1),n(1,:))
It doesn't make much odds.
  2 Comments
SF
SF on 9 Oct 2019
How did you plot this then? I'm getting that x and n aren't the same size.
John Doe
John Doe on 10 Oct 2019
Edited: John Doe on 10 Oct 2019
This was your size error. I've updated the answer to transpose n in to be the same as x.
size(x)
ans =
50 1
size(n)
ans =
1 50
Please accept answer :)

Sign in to comment.

Categories

Find more on Formatting and Annotation in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!