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Bubble sort for loop

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Matpar
Matpar on 3 Oct 2019
Commented: Guillaume on 4 Oct 2019
Hi can a professional guide me in terms of a bubble sort using 2 for loops please!
I have been googling to help myself but it's challenging to understand how they actually work! I have no code!
Thanx in advance for assisting me and responding to my questions!

Accepted Answer

Ajay Kumar
Ajay Kumar on 3 Oct 2019
Edited: Ajay Kumar on 3 Oct 2019
First try to understand the sorting algorithm. There are many videos on youtube that explains bubble sort.
Your data being x.
num = numel(x);
for j = 0 : num-1
for i = 1: num-j-1
if x(i)>x(i+1)
temp = x(i);
x(i) = x(i+1);
x(i+1) = temp;
end
end
end
  7 Comments
Rik
Rik on 4 Oct 2019
This code has nothing to do with your question. The sort function doesn't use bubble sort, because there are much more efficient algorithms for sorting.
Guillaume
Guillaume on 4 Oct 2019
Indeed what has that code to do with the initial question?
Note that in each of the proposed code it would be more efficient to stop as soon as the inner loop has done a pass without any swapping, rather than continue scanning the whole array.
"I was of the opinion that the for loop was the solution"
There's not much difference between a for loop and a while loop. That was my point to Kumar. You can always rewrite a for loop as a while loop and vice-versa
for i = 1:10
%do something
end
is equivalent to:
i = 1;
while i <= 10
%do something
i = i+1;
end
while:
while somecondition
%do something
end
is equivalent to
for i = 1:Inf
if somecondition
break;
end
%do something
end

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