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How to improve bit reading process in Matlab?
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I need to read a binary file and the Matlab coding is:
a = uint8(fread(fid,'ubit1')');
This is inefficient so I added a line below:
a = uint16(swapbytes(a));
But it doesn't help. Any other method to improve the bit reading process in Matlab?
14 Comments
Walter Roberson
on 6 Sep 2019
Is there any reason that you are not reading uint8? And possibly extracting bits afterwards? Either with bitget() or with a lookup table ?
Star Rats
on 6 Sep 2019
When I tried:
a = (fread(fid,'uint8')');
It shows error: Index exceeds the number of array elements (3529175).
As my project is a decoder where each block contains different number of bit.
And I need to read the input file bit by bit in order to execute the function in each block.
Walter Roberson
on 6 Sep 2019
bittable = (dec2bin(0:255, 8) - '0').';
a8 = fread(fid, 'uint8');
a = reshape( bittable(a8, :), [], 1);
Walter Roberson
on 6 Sep 2019
Edited: Walter Roberson
on 6 Sep 2019
a = reshape( bittable(double(a8)+1, :), [], 1);
Walter Roberson
on 6 Sep 2019
Your sync_word is wrong. It should be
syn = ones(1,12);
isMP2 = 1; %0 for MP4
layer = zeros(1,2);
sync_word = [syn, isMP2, layer];
Same total number of bits, but you had 0 1 for layer instead of 0 0.
Star Rats
on 6 Sep 2019
Hi @Walter, I think it is regardless of the syncword. It just couldn't go into the loop.
When I tested using the original coding, the if loop begins on the 1273th bit. But from the coding provided, it continues to scan the bit until the end without execute the if and for loop in between.
a = reshape( bittable(:,double(a8)+1), [], 1);
From the line above, is 'a' reading bit by bit or in an array form?
Walter Roberson
on 6 Sep 2019
It is reading byte by byte and translating to bits.
There is a theoretical possibility that the order of bits within a byte is reversed but it seems unlikely.
Walter Roberson
on 12 Sep 2019
Edited: Walter Roberson
on 12 Sep 2019
Yes, you can use gpu array. However it will slow down your code.
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