Fill an array with different size vectors

I have different sized vectors and an array to fill

A=[1,2,3,4];

B=[5,6];

C=[7,8,9];

ARRAY=zeros(5);

And I want to reach this:

OBJECTIVE =

1 2 3 4 0

5 6 0 0 0

7 8 9 0 0

0 0 0 0 0

0 0 0 0 0

Any idea? Also if there is any way to extend vectors to certain length I highly appreciate to know.

Answer 1

[Stephen23]

For an arbitrary number of vectors use a cell array, then looping is trivial:

>> D = {[1,2,3,4],[5,6],[7,8,9]};
>> M = zeros(5,5);
>> for k = 1:numel(D), M(k,1:numel(D{k})) = D{k}; end
>> M
M =
  1  2  3  4  0
  5  6  0  0  0
  7  8  9  0  0
  0  0  0  0  0
  0  0  0  0  0

Answer 2

[the cyclist]

Here is one straightforward way:

A=[1,2,3,4];
B=[5,6];
C=[7,8,9];
ARRAY=zeros(5);

ARRAY(1,1:numel(A)) = A;
ARRAY(2,1:numel(B)) = B;
ARRAY(3,1:numel(C)) = C;

[Aena]

it works. Thanks!

Answer 3

[Diego R]

Thank you both! I'd never had found this "numel" by myslef.

Answer 4

[Jos (10584)]

A=[1,2,3,4];
B=[5,6];
C=[7,8,9];
[ARRAY, tf] = padcat(A,B,C) % pad with NaNs
ARRAY(~tf) = 0 % replace those NaNs with zeros

PADCAT concatenates vectors of unequal lengths by padding them with NaNs. It is available for free on the File Exchange

https://www.mathworks.com/matlabcentral/fileexchange/22909-padcat