Index exceeds the number of array elements (1). Caused by: Failure in initial nonlinear constraint function evaluation. FMINCON cannot continue.
3 views (last 30 days)
Show older comments
BrokenDreams
on 16 Jul 2019
Commented: Walter Roberson
on 16 Jul 2019
My OBJECTIVE FUNCTION:
function f=objective2(h,x,F_r,T_r,UA_r,n)
options.Display='off';
%FlowStreams
x(1)=F_r(1);
x(2)=h;
x(6)=x(1)-x(2);
x(3)=x(2);
x(7)=x(6);
x(4)=x(3);
x(8)=x(7);
x(5)=x(4);
x(9)=x(8);
x(10)=x(5)+x(9);
x(11)=F_r(11);
x(12)=x(11);
x(16)=F_r(16);
x(17)=x(16);
x(18)=F_r(18);
x(19)=x(18);
x(20)=F_r(20);
x(21)=x(20);
x(13)=F_r(13);
x(14)=x(13);
x(15)=x(14);
%TempDependent
x(n+1)=T_r(1);
x(n+2)=T_r(2);
x(n+6)=T_r(6);
x(n+11)=T_r(11);
x(n+13)=T_r(13);
x(n+16)=T_r(16);
x(n+18)=T_r(18);
x(n+20)=T_r(20);
%Temp Independent
d1=fsolve(@(k)solve1(k,x,UA_r,n),[T_r(7),T_r(17)],options);
x(n+7)=d1(1);
x(n+17)=d1(2);
d2=fsolve(@(k)solve2(k,x,UA_r,n),[T_r(8),T_r(19)],options);
x(n+8)=d2(1);
x(n+19)=d2(2);
d3=fsolve(@(k)solve3(k,x,UA_r,n),[T_r(9),T_r(21)],options);
x(n+9)=d3(1);
x(n+21)=d3(2);
d4=fsolve(@(k)solve4(k,x,UA_r,n),[T_r(3),T_r(15),T_r(14),T_r(12),T_r(4),T_r(5)],options);
x(n+3)=d4(1);
x(n+15)=d4(2);
x(n+14)=d4(3);
x(n+12)=d4(4);
x(n+4)=d4(5);
x(n+5)=d4(6);
q = roots([0.000505*(x(5) + x(9)) 0.444*(x(5) + x(9)) -(0.444*(x(5)*x(n+5) + x(9)*x(n+9)) + 0.000505*(x(5)*x(n+5)^2 + x(9)*x(n+9)^2))]);
for k = 1:2
if q(k) > x(n+5) && q(k) < x(n+9)
x(n+10) = q(k);
break;
elseif q(k) > x(n+9) && q(k) < x(n+5)
x(n+10) = q(k);
break;
elseif k == 2
k=k+1;
end
end
f=-x(n+10);
end
Please Help
0 Comments
Accepted Answer
Walter Roberson
on 16 Jul 2019
constraint2 will be called with a vector the same size as the vector passed to the objective function. Your x0 in your fmincon call is the scalar value 130, so the vector being passed to the objective function and to the constraint function will be a scalar.
You are confusing yourself by talking about x0 and x but also using @(h) defining your objective function. The x that is built inside your objective2 is not the x that will be passed to your constraint function. Perhaps you might need to build that x vector inside your constraint function as well.
4 Comments
Walter Roberson
on 16 Jul 2019
[y,fval]=fmincon(@(h)objective2(h,F_r,T_r,UA_r,n),x0,a,b,aeq,beq,lb,ub,@(h)constraint2(h,x,F_r,T_r,UA_r,n),options);
More Answers (0)
See Also
Categories
Find more on Loops and Conditional Statements in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!