Difficulty storing Output from Loop (Unable to perform assignment because the size of the left side is 1-by-1 and the size of the right side is 2-by-1)

This loop works -

for i=1:19
x(find(y(start(i):end(i),:)
    ==max(y(start(i):end(i),:)))+ (start(i)-1))
end

However, when I try to store the answers in a matrix:

MatrixName = []
for i = 1:19;
MatrixName(i,:) = x(find(y(start(i):end(i),:)
    ==max(y(start(i):end(i),:)))+ (start(i)-1))
end

I get the following error:

%Unable to perform assignment because the size of the left side is 1-by-1 and 
% the size of the right side is 2-by-1.

I think the reason is because in one of the loop iterations there are 2 answers instead of 1 (there are 2 x values when the variable y is at it's max). I can further confirm this because it actually does store the values in a matrix until it gets to that specific trial with 2 values, so that's probably the reason. How would I be able to store these answers?

Answer 1

[Jan]

To store arrays of different sizes, use a cell array:

KMaxSBPFullTime = cell(1, 19);
for i = 1:19
  KMaxSBPFullTime{i} = ...

By the way, your code is extremely hard to read. Shorter names would increase the readability:

Result = cell(1, 19);
K5     = KFiveMinTimes;
Kend   = KEndMinTimes;
SBP    = KetamineRaw.SBP;
Time   = KetamineRaw.Time;
for k = 1:19
  tmp       = SBP(K5(k):KEnd(k),:);
  Result{k} = Time(find(tmp == max(tmp)) + K5(k) - 1);
end

[Jay Vankawala]

Thanks for the tips!