How can i fix ' Unable to perform assignment because the left and right sides have a different number of elements.' in the loop functions ?

I got errors in Rdot, alpha3, Rdot2

 R2= 16;
 R3=33;
 omega2= 3;

 i=0;
 j=0;
 
 for theta2= 0:5:180;
    theta2=theta2*pi/180;
    i=i+1;
    x(i)=theta2;
    
    %position
    theta3 = pi - asin(R2*sin(theta2)/R3);
    R1(i)= (R2*cos(theta2) - R3*cos(theta3));
    %velocity
    omega3 (i) = (omega2*R2*cos(theta2))/(R3*cos(theta3));
    Rdot(i) = (-R2*omega2*sin(theta2))+ (R3*omega3*cos(theta3)); 
    
    %acceleration 
    alpha3 (i) = ((-omega2.^2)*R2*sin(theta2)+ (omega3.^2)*R3*sin(theta3))/R3*cos(theta3); 
    Rdot2(i) = -R2*(omega2^2)*cos(theta2) + R3*alpha3*sin(theta3) + R3*(omega3^2)*cos(theta3) 
    
    theta33(i) = theta3*180/pi;
    theta22(i) =theta2*180/pi;
 end

[per isakson]

BTW, doc says: "Avoid assigning a value to the index variable within the loop statements."

Answer 1

[infinity]

Since "omega3" is a vector, which is not scalar and you calculate alpha3 by using omega3. So, I suggest you change "omge3" in

Rdot(i) = (-R2*omega2*sin(theta2))+ (R3*omega3*cos(theta3)); 
    
    %acceleration 
    alpha3 (i) = ((-omega2.^2)*R2*sin(theta2)+ (omega3.^2)*R3*sin(theta3))/R3*cos(theta3); 

by

    omega3(i)

If this is not your formula, you should check it again.

Answer 2

[per isakson]

One thing is to make a code run without throwing errors, another is to make it produce the intended result.

Replacing omega3 by omega3(i) and alpha3 by alpha3(i) in the right hand side of the lines, which throw errors, makes the code run.