To get autocorrelation function of periodic signal with xcorr function
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I couldn't get autocorrelation function of my periodic signal with xcorr() function as I have expected. My signal is periodic and its autocorrelation function should be periodic with same amplitudes, I got transient signal when I used xcorr() function. Where is the mistake?
clc,clear,close all
T=2;A=2; %period and amplitude of signal
t=linspace(-4*T,4*T,1000);
x=mod(t,T)
x=A*(-x+A/2)%Periodic signal which it's autcorr. will be determined
plot(t,x,'linewidth',2);
ylim([-4 4]);
grid on
xlabel('t');ylabel('x(t)');title('Real Function, T=2, A=2');
%return
a=xcorr(x,((length(t))/2));
dt=median(diff(t)); % diff() calculates distance between adjacent elements in vector, median() avaraging
a=a*dt; %xcorr function calculate corelation as a discrete time signal, we converted to continous time signal
t(1001)=t(1000)+dt;
plot(t,a,'r');hold on
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Answers (1)
Luis J Gilarranz
on 26 May 2019
No idea about xcor function, but you can write a lower level code that does the job:
Autocorrelation is just the pearson correlation coefficient between a time series and the same time series but with a lag. In this code I do the lag-1 autocorrelation inside a moving window of 100 datapoints.
clc,clear,close all
T=2;A=2; %period and amplitude of signal
t=linspace(-4*T,4*T,1000);
x=mod(t,T)
x=A*(-x+A/2)%Periodic signal which it's autcorr. will be determined
%I transpose x so that it works with the code I had
x=x'
HalfMW=50;%half of the moving window
cont=0;
AutCorVsTime=zeros(cont,1);
for d=HalfMW+1:1000-HalfMW
cont=cont+1;
Chunk = x(d-HalfMW:d+HalfMW,1);
SizeChunk = size(Chunk,1);
AutCorVsTime(d,1)=corr(Chunk(2:SizeChunk,1),Chunk(1:SizeChunk-1,1),'rows','complete'); %Pearson correlation coefficient ignoring NaN
end
plot(AutCorVsTime)
And as you can see the resulting figure is indeed periodic.
If you change the size of the moving window the plot obviously changes.
2 Comments
Asrith Pyla
on 6 Jun 2020
Dear Luis, is it possible to determine the auto-correlation function for an image?
Luis J Gilarranz
on 9 Jun 2020
Edited: Luis J Gilarranz
on 9 Jun 2020
Yes, by taking a radious around a pixel. Search for autocorrelation in 2D
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