Populate structure array efficiently

Hi,

I am wondering if this question is too simple and if I am missing something important. How do I efficiently populate a structure array such that

A = 6:10;

and the resulting structure array is

S(1).A = 6;
S(2).A = 7;
...
S(5).A = 10;

Using a loop S is fairly easy to obtain, but there are probably much more efficient ways to do so.

Regards, Anon

Answer 1

[Andrei Bobrov]

S = struct('A',num2cell(A))

[Anon]

Aargh, I knew it should be easy. Thanks!

Answer 2

[Walter Roberson]

It can be done, but it is not pretty.

S = struct( 'A', num2cell(6:10) )