How to sort rows of a matrix without using sortrows function?

Write a function to realize the function of sortrows.

I wrote a simple sort function, but our teacher said that we can use less than five lines of code to achieve, I do not know how to improve

function A = sortrows( A )
[m,n]=size(A);
for N=1:m-1
   for M=N+1:m
       if A(N,1)>A(M,1)
           t=A(N,:);
           A(N,:)=A(M,:);
           A(M,:)=t; 
       
       else if A(N,1)==A(M,1)
           ll=0;
           rr=0;
           k=1;
           while k<n
               ll=ll+A(N,k);
               rr=rr+A(M,k);
               if(ll>rr)
                 t=A(N,:);
                 A(N,:)=A(M,:);
                 A(M,:)=t;   
               end
           end
       end
       M=M+1;
   end
   N=N+1;
end
disp(A);
end

[Stephen23]

@yijie yu: what have you tried so far?

[yijie yu]

I've already posted it up, and I'd like to get some Suggestions for simplifying functions

[Stephen23]

@yijie yu: are you allowed to use sort ? If so, then you can implement a simple sortrows function with one loop and a few lines of code.

Answer 1

[Raj]

How about doing a small search and putting a little effort before dumping your homework question here!

See this.

[yijie yu]

I wrote a simple sort function, but our teacher said that we can use less than five lines of code to achieve, I do not know how to improve