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counting no .of temperature less than 32 in array

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Abhishek singh
Abhishek singh on 3 Apr 2019
Closed: madhan ravi on 30 Aug 2020
function numfreeze = freezing(v)
count = 0;
i =v()
j = 32
if i < 32
count = count+1
numfreeze = count
else
end
  1 Comment
Abhishek singh
Abhishek singh on 3 Apr 2019
geeting errror
i =
45 21 32 31 51 12
j =
32
Output argument "numfreeze" (and maybe others) not assigned during call to "freezing".

Answers (6)

Ngei Katumo
Ngei Katumo on 22 Aug 2019
function w = freezing (A)
w = sum (logical (A(A<32)));
end

madhan ravi
madhan ravi on 3 Apr 2019
v=[45 21 32 31 51 12];
threshold=32;
numfreeze = freezing(v,threshold) % function call
function numfreeze = freezing(v,threshold) % function definition
numfreeze = nnz(v<threshold);
end
  6 Comments
Image Analyst
Image Analyst on 11 Jun 2019
You mean freezing.m, since that's what was asked.

Nazneen Sayyad
Nazneen Sayyad on 10 Jun 2019
Write a function called freezing that takes a vector of numbers that correspond to daily low temperatures in Fahrenheit. Return numfreeze, the number of days with sub freezing temperatures (that is, lower than 32 F) without using loops. Here is an example run:
numfreeze = freezing([45 21 32 31 51 12])
numfreeze =
3
function numfreeze = freezing(A)
B=A(A<32);
numfreeze=numel(B);
end

Ajith Thomas
Ajith Thomas on 19 Jul 2019
function numfreeze=freezing(w)
lowerthan_32=w(w<32);
no_logical_values=lowerthan_32(lowerthan_32>=0);
numfreeze=length(no_logical_values);
end
  1 Comment
Ajith Thomas
Ajith Thomas on 19 Jul 2019
function numfreeze=freezing(w)
lowerthan_32=w(w<32);
numfreeze=numel(lowerthan_32);
end

Roshan Singh
Roshan Singh on 15 Sep 2019
function numfreeze = freezing(x)
f = x(x<32);
numfreeze = length(f);
end

MADHURJYA DAS
MADHURJYA DAS on 30 Aug 2020
function numfreeze=freezing(A)
x=(A<32);
numfreeze=sum(x(:));
end

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