Compare to rows and delete matching rows

Update: I have attached to mat files. I want to compare the rows in file A to that of file B. If a number in the first column of B matches with that of a number in the first column of A, then the entire row in A in which the number matches with that in B should be deleted. So example if you look at file B, the number 12 is in column 1, row 2 and it matches with column 1, row 4 in A. In this case I want a code that will delete the entire row 4 in A. I will now be left with 6by4 matrix. I am trying to compare the headers and use it as a quide to remove rows in A that I dont want. I have a very large data set and having a code that can do this will be very helpful.
Thanks!

4 Comments

Your screenshots look like your data is still in Excel and not yet in Matlab arrays. Once they are in Matlab you should be able to use ismember. What have you tried so far?
I transfered them to matlab but the ismember function is not helping. Maybe its my code
Make it easy for people to help you by attaching your Excel workbook.
@Image Analyst
Thanks for the information. I have attached to mat files. I want to compare the rows in file A to that of file B. If a number in the first column of B matches with that of a number in the first column of A, then the entire row in A in which the number matches with that in B should be deleted. So example if you look at file B, the number 12 is in column 1, row 2 and it matches with column 1, row 4 in A. In this case I want a code that will delete the entire row 4 in A. I will now be left with 6by4 matrix.
Thanks!

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 Accepted Answer

[~,ib]=ismember(A,B(:,1));
B(ib,:)=[];

3 Comments

This is the error message I received in matlab
Subscript indices must either be real positive integers or logicals.
Show your work...
>> A
A =
11
14
>> B
B =
11.0000 0.0522 0.7477
14.0000 0.5712 0.3202
12.0000 0.4929 0.2217
>> [~,ib]=ismember(A,B(:,1))
ib =
1
2
>> B(ib,:)=[]
B =
12.0000 0.4929 0.2217
>>
Works to solve the described problem...
It works!
Thank you!

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Asked:

on 10 Mar 2019

Commented:

on 11 Mar 2019

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