Making Different Length Vector Same Length
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I have two sets of data, stress and strain. Strain is [9x1] and stress is [12x1]. I need both vectors to be the same length, which would be [12x1]. I have tried using the interp1 function, but in order to use this it seems as though the inputs, which would be stress and strain, have to be the same size already. I am not sure if this is even the right direction. I have provided my raw stress and strain data if someone would like to help or provide any sample code. Thank you in advance!
stress = [1.854621961
397.953227
680.5854525
1319.335498
1569.283812
2489.328323
3585.957167
4591.466307
5916.213652
7592.943924
8625.360283
9808.244251];
strain = [0.001170792
0.005019681
0.010524187
0.017380968
0.026422366
0.034377908
0.04229767
0.050683195
0.059544219
];
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Accepted Answer
Star Strider
on 22 Feb 2019
Edited: Star Strider
on 22 Feb 2019
One approach:
strainNew = interp1((1:numel(strain)), strain, linspace(1, numel(strain), numel(stress)), 'linear')';
figure
plot((1:numel(strain)), strain)
hold on
plot(linspace(1, numel(strain), numel(stress)), strainNew)
hold off
It creates a 12-element vector with the same beginning and ending values as the original vector to do the interpolation.
EDIT — Added transpose operator (') to create (12 x 1) vector,, added plot. Original code otherwise unchanged.
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More Answers (2)
Jos (10584)
on 22 Feb 2019
Edited: Jos (10584)
on 22 Feb 2019
[EDITED] This might work for you:
ix = linspace(1, numel(stress), numel(strain))
NewStrain = interp1(ix, strain, 1:numel(stress))
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