calling function return only one iteration answer

I have this sacent method function. it works fine while testing it.

function [root, ea, iter] = secant(f, xi, xs, es, maxit)

    iter=0;
    
    while(true)
        root = xi - (f(xi) * (xi-xs))/(f(xi)-f(xs));
        
        xs = xi;
        xi=root;
        iter=iter+1;
        
        if root~=0
           ea= abs((xi-xs)/xi)*100; 
        end
        
        if iter >=maxit || ea<=es
            break;
        end 
    end
end 

But when i call it like following it only returns 1st iteration values.

[root, ea, iter]= secant(@(x)x^2-9,2,5,0,.01,5)

Output:

root =  2.7143
ea =  26.316
iter =  1

But original output:

root =  3.0000
ea =  0.0010005
iter =  5

What am i doing wrong?

Answer 1

[Walter Roberson]

You are passing in 6 inputs to a function that expects 5. Current versions of MATLAB (as far back as I can recall) would refuse to run the function.

I suspect that instead of 0,.01 you intended 0.01

[Asaduzzaman Sarker]

Thankyou. it was my fault.