How to remove a percentage of image counting from the bottom to top
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Stelios Fanourakis
on 30 Jan 2019
Commented: Stelios Fanourakis
on 30 Jan 2019
Hi
I want to subtract a portion of image (e.g. 30% of it from the top). How do I do that?
If I do, something like this,
img = (croppedImage - (croppedImage.*0.3));
I usually get a 30% deduction from the bottom of it. I want this deduction to be from the top.
Moreover, I need a method to translate the deduction to number of rows. To be known, how many pixel rows this 30% of the image is.
Any ideas please?
1 Comment
Rik
on 30 Jan 2019
Do you want to change the size of your image, or the ensities that make up that image?
Accepted Answer
Mark Sherstan
on 30 Jan 2019
Edited: Mark Sherstan
on 30 Jan 2019
Look at the example I wrote for you below. Use the size function and realize that imcrop takes an array in the form of [xPosition yPosition width height] where the (0,0) point is the top left corner of your image.
I = imread('test.png');
[height width dims] = size(I);
J = imcrop(I,[0 floor(height*0.3) width height-floor(height*0.3)]);
figure(1)
subplot(1,2,1); imshow(I)
subplot(1,2,2); imshow(J)
3 Comments
Mark Sherstan
on 30 Jan 2019
Glad it worked! You could do something along the lines of this:
I = imread('test.png');
[height width dims] = size(I);
rows30 = floor(height*0.3) % I used floor but you can use ceil, round, etc...
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