Count number of repeated element before next different number in array?
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Hi,
This is the problem:
I have an array of size 1xN, and this array is filled with 1 and 0. What I want is to count the number of repeated ones before a zero.
I will try to explain with an example.
A = [1,1,1,0,0,0,0,1,0,0,1,1,0,0,0,1,1,1,1];
What I want the code to do is to count how many times the ones are repeated before a zero. So, the answer is
OnesRepeated = [3, 1, 2, 4]
Can anyone help please? Thanks
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Accepted Answer
More Answers (1)
Adam
on 14 Jan 2019
runs = diff( [0 find( diff( A ) ) numel( A )] )
if A(1) == 1
OnesRepeated = runs( 1:2:end );
else
OnesRepeated = runs( 2:2:end );
end
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