Find matches without repetition from two cell arrays + extra condition
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Alberto Cuadra Lara
on 6 Dec 2018
Commented: Alberto Cuadra Lara
on 6 Dec 2018
Hello,
In order to reduce the size of a matrix I need to find all the elements of the periodic table (patterns - cell 1) of all the species considered (cell 2). Also, it has to take in account every number as the end of the evaluable pattern.
Example:
Elements = {'H', 'He', 'Li', .... };
NameSpecies = {'H2','O2','H2O2','CH2OH','C'};
Desired_Result = {'H','O','C'};
At the moment I'm using this piece of code that I found on the net
Match=cellfun(@(x) ismember(x,NameSpecies), Elements, 'UniformOutput', 0);
Elements = Elements(cell2mat(Match));
but this function is only going to give me the same individuals elements, in the case of the example the result is
Result = {'C'};
Any suggestion to tackle it without brute force?
Thanks for your time!
2 Comments
Accepted Answer
Bruno Luong
on 6 Dec 2018
You don't even need the period table, assuming element start with an Uppercase eventually followed by lower-case
NameSpecies = {'He','O2','H2O2','CH2OH','C'};
Tmp = cell(size(NameSpecies));
for k = 1:length(Tmp)
Specie = NameSpecies{k};
Specie(Specie>='0' & Specie<='9') = ' ';
idx = find([(Specie>='A' & Specie<='Z'), true]);
lgt = diff(idx);
Tmp{k} = strtrim(mat2cell(Specie, 1, lgt));
end
El = unique(cat(2,Tmp{:}))
The result is:
El =
1×4 cell array
{'C'} {'H'} {'He'} {'O'}
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