Solve the general solution of a Differential equation with boundary conditions

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Hi
I have the general solution of a differential equation and the boundary conditions. How can I solve this?
w(x)=C1+C2*x+C3*(x^2)+C4*(x^3)+(L^4)*C5*cosh(x/L)+(L^4)*C6*sinh(x/L)
w(0)=0
w'(0)=0
w''(0)=0
w''(L)=0
w'''(L)-(L^2)*w'''''(L)=F/(E*I)
w''(L)-(L^2)*w''''(L)

Accepted Answer

Torsten
Torsten on 29 Nov 2018
Tell the program which gave you the general solution to additionally incorporate the six boundary conditions.
  2 Comments
Vlasis Demosthenes
Vlasis Demosthenes on 29 Nov 2018
I don't have the exact differential equation from which the general solution emerged.
Is there any way to solve this? from the general solution and the boundary conditions only?
Torsten
Torsten on 29 Nov 2018
Build w', w'', w''' and w'''' of w and evaluate the conditions. You'll arrive at a linear system of equations in the Ci's as unknowns.
I'll do it for the first two conditions:
w(0)=0 leads to
C1+C2*0+C3*(0^2)+C4*(0^3)+(L^4)*C5*cosh(0/L)+(L^4)*C6*sinh(0/L) = 0, thus
C1 + L^4*C5 = 0
w'(0)=0 leads to
C2+2*C3*0+3*C4*(0^2)+(L^4)/L*C5*sinh(0/L)+(L^4)/L*C6*cosh(0/L) = 0, thus
C2 + L^3*C6 = 0
...
Once you have the equations, write them as a system of linear equations in the form A*C = b with a 6x6 matrix A and a 6x1 vector b.
Then C is given by
C=A\b
Best wishes
Torsten.

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