Checking if a matrix is symmetric

Hi
i want to check if the matrix is symmetric or not by using nested loops and display a certain message if it is or not. the problem is that it's displaying the message after comparing each element of the original matrix with the ones in the transposed or inversed matrix.. i want the message to be displayed after both matrices are compared!.
A = [ 2 6 9; 7 3 8; 10 11 12];
for i = 1:3
for j = 1:3
if(A(i,j) == A(j,i))
disp('true')
else
disp('false')
end
end
end

 Accepted Answer

disp(isequal(A,A.'))

9 Comments

it printed zeros.. what im looking for is that it prints one of the following :
disp('The matrix is symmetric!');
%or
disp('The matrix is asymmetric!');
fprintf(['The matrix is a' repmat('\b',isequal(A,A.')) 'symmetric!\n'])
thank you so much.. how can i make it print the command once?
? That already displays the output once.
it displays it three times! Where i should include the print statement?
I suspect that you put Bruno's code into a loop. Instead it should be the entire code. It does it all including the displaying. No loop.
A = [ 2 6 9; 7 3 8; 10 11 12];
fprintf(['The matrix is a' repmat('\b',isequal(A,A.')) 'symmetric!\n']);
i want the matrix to be checked with nested loops.. that's what im trying.... Bruno's Answer does work but with loops it repeats the message!
A = [ 2 6 9; 7 3 8; 10 11 12];
for i = 1 : 1
for j = 1 : 1
fprintf(['The matrix is a' repmat('\b',isequal(A,A.')) 'symmetric!\n']);
end
end
Thanks alot! it worked <3

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