Trying to in do a vector in a for loop

clc
n=input('Enter number of rows: ');
m=input('Enter number of column: ');
matrix = zeros(n, m); % preallocate your matrix
for k=1:n
for i = 1:m
    M(i) = input(['Enter row ' num2str(k) ' column ' num2str(i) ' number: ']);
    matrix(:,i) = M(i);
end
end
A=[matrix]

Im trying to input numbers for the first row with a set number of columns and once that is done i need it to move on to next row. At the end im trying to show them as one matrix. I cant seem to find a way or know a way that allows me to save the inputs as one row and be able to call on that row for however many rows there are.

I guess i want the solution to look like this when i call on it. That s

A =

     1     0     2
     3     4     5
     4     5     8

Answer 1

[madhan ravi]

n=input('Enter number of rows: ')
m=input('Enter number of column: ')
matrix = zeros(n, m); % preallocate your matrix
for k=1:n
for i = 1:m
   matrix(k,i) = input('input number: ') 
end
end
A=matrix

Answer 2

[KSSV]

m = 3 ; n = 3 ;
A = zeros(m,n) ;
for i = 1:m
    for j = 1:n
        prompt = sprintf('(%d,%d) element:',i,j) ;
        A(i,j) = input(prompt) ;
    end
end

Once your matrix is ready, you can do what ever you want.