c file name from grt generated code

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I have a tlc file which accesses the c file name generated through grt.tlc
%assign modelFileName = LibGetSourceFileSection(fileIdx, "Name")
Some times without any reason, the above code returns the complete path of the file and at most times only the name of the c or header file.
How can i filter out the complete path details and get only the file name from the string that is returned above?
Example Most of the time, modelFileName is populated as file name.c or file name.h Some times, it comes back as D:\MyGenFiles\StorageLoc\_sharedutils\<c file name>.c
How do i remove the "D:\MyGenFiles\StorageLoc\_sharedutils\" part from the string above in tlc.
I have to do this only in the tlc environment.

Accepted Answer

Mark McBroom
Mark McBroom on 11 Jan 2019
Probably the easiest approach is to write a simple MATLAB function that takes as an argument the modelFileName, then uses fileparts() to strip off the directory name and returns the file name. Then call this MATLAB function from TLC using the built-in TLC function FEVAL().
  1 Comment
Chirag Jagadish
Chirag Jagadish on 11 Jan 2019
Exactly what i did. I made a new m file for this and made the FEVAL call it. FEVAL call from tlc makes only the first parameter available in the tlc. So i made a suitable m file and called it.
Thanks for the answer though

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