How to solve this only using looping

For example A=(aa bb cc dd) and B=(aa bb xx yy zz) then i want to display like this (xx yy zz)

How to display like that by using looping only...??

Answer 1

[Image Analyst]

Try this:

A = [1,2,3,4]
B = [1,2,8,9,10]
lengthA = length(A);
lengthB = length(B);
maxLength = max([lengthA, lengthB])
for k = 1 : maxLength
  if k <= lengthA && k <= lengthB
    if A(k) ~= B(k)
      fprintf('%.1f ', B(k));
    end
  elseif k > lengthA && k <= lengthB
      fprintf('%.1f ', B(k));
  elseif k <= lengthA && k > lengthB
      fprintf('%.1f ', A(k));
  end
end
fprintf('\n');

[Yoga Arviansyah]

If the array is string what should i change ?? To make it work ??

[Image Analyst]

You'd need to convert the string to numbers with something like sscanf() or textscan(), or strsplit() along with str2double().

Answer 2

[Bish Erbas]

One way of accomplishing this would be:

A = [1 2 3 4 8 9];
B = [1 2 3 4 5 6 7];

for k = 1:numel(A)
    B(B==A(k))=[];
end