converting a 1x4096 cell, containing binary to 1x(4*4096) double containing binary codes

Hi,

My code generates a x by y matrix, containing random numbers within range of (0 to Order-1) as follow:

x=600; y=8; order=16; bits=randint(x, y ,order,1);

I convert the each integer value to binary as follow

binary=dec2bin(bits,log2(order));

which result in a matrix of class char. I then convert it into a cell array as follow

binary=cellstr(binary); binary=binary';

which results in a long cell row of lenght 4096 where each cell has log2(order) bits. how can I convert this row. such that I will have each single bit in a seperate cell of double class. such that I will end up with a 1x(4*4096) double

Many thanks

Answer 1

[Walter Roberson]

binary = (dec2bin(bits,log2(order)) - '0') .' ;

With no cellstr()