Spliting a n-by-3 Array into several different arrays.

So, I have the following array:

v = 
[1 2 3;
-1 2 -3;
0 0 0;
1 -2 3;
1 2 3;
1 2 3;
0 0 0;
0 0 0;
1 1 1]

I would like to split it into several arrays that I can call upon later as follows:

v_1 = [1 2 3; -1 2 -3], 
v_2 = [1 -2 3; 1 2 3; 1 2 3], 
v_3 = [1 1 1];

How would I go about doing this. I would like to use the zeros as an indication of where to create another variable with the array indicated.

Thank you.

[Scott Salazar]

I was hoping to use what Star Strider did in his example, and make a variation on it. Would this be a proper approach to my problem?

[Scott Salazar]

So, I have something now, looks like the following:

v = [1 2 3; -1 2 -3; 0 0 0; 1 -2 3; 1 2 3; 1 2 3; 0 0 0; 0 0 0; 1 1 1];
idx = all((v),2);
idr = diff(find([1;diff(idx);1]));
D = mat2cell(v,idr(:),size(v,2));
D{1:2:end}

Where the value of D{1:2:end} is:

ans =

     1     2     3
    -1     2    -3

ans =

     1    -2     3
     1     2     3
     1     2     3

ans =

     1     1     1

Which is close to what I want, but I would again like to call them each from a vector. Thoughts?

[Scott Salazar]

Excuse me, I meant to ask that the output will be in several different arrays.

[dpb]

I know you asked that, but do NOT go down that perilous pathway..."There be dragons!"

[Stephen23]

"...but I would again like to call them each from a vector. Thoughts?"

Do NOT do that. Magically accessing variable names is one way the beginners force themselves into writing slow, complex, buggy code. Here is why:

https://www.mathworks.com/matlabcentral/answers/304528-tutorial-why-variables-should-not-be-named-dynamically-eval

Answer 1

[dpb]

v is not a vector but an array.

Star's code works on a vector; would be painful to extend to an array I think, as is. BUT, you can create a vector to use to find the split locations by his technique and then select the array instead of vector.

Define the auxiliary vector as

aux=all(v==0,2);