Comparing elements within a cell array

Hi everyone, I have two cell arrays x and y. I want compare values of x based on y. Like x{1,1} in y contains [2,4]. So it will compare 1st element of x which is [4,7,8] with 2nd and 4th element of x and get the common values. then 2nd element of x is compared with 1st and 4th element of x because 2nd element of x is [1,4] and so on.
x= {[4,7,8];[1,5,6];[1,7,8],[1,4]}
y= {[2,4];[1,4];[1,2,4],3}
Result will look like this:
result{1,1} = {0;[7,8]} %comparison of x{1,1} with x{2,1} and x{4,1}
result{2,1}= {0;1} %comparison of x{2,1} with x{1,1} and x{4,1}
result{3,1}= {[7,8];1;1} %comparison of x{3,1} with x{1,1}, x{2,1} and x{4,1}
result{4,1}={1} %comparison of x{4,1} with x{3,1}
Zero is placed where there is no common values found.
Thanks in advance.

3 Comments

Stephen23
Stephen23 on 18 Aug 2018
Edited: Stephen23 on 18 Aug 2018
@lucksBi: Zero is not a "common value" to any of those arrays, so where does the zero come from? Why not just use an empty array?
In any case, this would be quite easy to achieve using loops and intersect, so I am sure that you must have written something. Please show us what you have tried so far.
lucksBi
lucksBi on 18 Aug 2018
Edited: lucksBi on 18 Aug 2018
Sorry about that.. Actually zero is replaced with empty value.
Actually i want to do it without using loops because i have a large dataset on which i will run the code
I doubt there is a direct method of doing this. You could try to parallelize this by using parfor or cellfun.

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on 18 Aug 2018

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Rik
on 18 Aug 2018

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