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isa not recognizing Line or Figure class

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I wanted to test whether input data of a function is a Line object using something like:
>>
x=-2*pi:.01:2*pi;HLine=plot(sin(2*x));
However, now isa(HLine,'Line') returns false! So far, isa has faithfully recognized my self-made classes. Why doesn't it recognize Line?

Accepted Answer

Guillaume
Guillaume on 10 Aug 2018
>> x=-2*pi:.01:2*pi;HLine=plot(sin(2*x));
>> class(HLine)
ans =
'matlab.graphics.chart.primitive.Line'
>> isa(HLine, 'matlab.graphics.chart.primitive.Line')
ans =
logical
1
You need to use the fully qualified name of the class

More Answers (1)

KSSV
KSSV on 10 Aug 2018
x=-2*pi:.01:2*pi;
HLine=plot(sin(2*x));
strcmp(HLine.Type,'line')
  2 Comments
Guillaume
Guillaume on 10 Aug 2018
Note that the Type property of a graphics object is not relevant for isa.
KSSV
KSSV on 10 Aug 2018
Yes....thats why I used strcmp to check is it a Line type.

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