How to calculate function for different parts of array with values of same lenght in one big array

Can anyone help me solve this problem? I have for example this array of values: T =

   40.9992
   40.9992
   44.3003
   44.3003
   41.0270
   41.0270
   41.2030
   41.2030
   43.1300
   43.1300
   44.6121
   44.6121
   41.6218
   41.6218
   41.3046
   41.3046
   44.5307
   44.5307
   47.1521
   47.1521
   45.7819
   45.7819
   41.7752
   41.7752
   42.7205
   42.7205
   42.2346
   42.2346
   42.1536
   42.1536
   41.0068
   41.0068
   43.9901
   43.9901

and I would like to calculate mean (or another function) for each 5 values in the the array (therefore for 1:5, 6:10, 11:15 and so on.. till the end). Is it somehow possible do it in one command or loop that I will receive means for each block of values in one time/answer, eventually in table output. Thank you very much in advance.

Answer 1

[Guillaume]

Assuming the number of elements in the vector is a multiple of 5, you can just reshape the array into a matrix of 5 rows and calculate the mean across the rows (the default), so:

mean(reshape(yourvector, 5, []))

If the number of elements is not a multiple of 5, then you need to explain what should happen for the few leftover elements.

[Jaroslav Krc]

Thank you very much, it works :-), nice. All right, but if the number of values is not a multiple of 5, how the function would look like when we would like to have the mean also from leftovers? Is it somehow possible to implement this into one command/function? Thank you very much again. J.

[Guillaume]

The simplest way is to append NaN to the vector to make its length a multiple of 5, reshape it, then calculate the mean with the 'omitnan' option:

extendedvector = [yourvector; nan(mod(-numel(yourvector), 5), 1)];  %append as many nans as necessary to make length a multiple of 5
result = mean(reshape(extendedvector, 5, []), 'omitnan')