Scatter not working in 2018

Hi, I can't get the "scatter" function to work using the option to input a vector to set the marker colors.

Here's the example in the 'help' text:

x = linspace(0,3*pi,200);
y = cos(x) + rand(1,200);
c = linspace(1,10,length(x));
scatter(x,y,[],c)

When I run this I get the following error: "Warning: Error updating Scatter. Not enough input arguments."

I have just upgraded to the 2018 release and use this function frequently. It works if you set the color in other ways (e.g. as a constant, or bunch of rgb triplets), but I'd specifically like to use a vector to color my markers.

Any help appreciated!

[dpb]

Looks like they broke it...bug report time.

Just to be sure, what does

which -all scatter

return to ensure something isn't aliasing the correct routine.

[Albert Fan]

I've tried myself and running into no errors using R2018a, can you provide more context of your problem, maybe you have some other variables floating around that makes this error?

[dpb]

Just saw something I missed...the error says

: "Warning: Error updating Scatter. Not enough input arguments."

"Scatter" is capitalized...is that a klew?; the ML routine is all lowercase.

[Walter Roberson]

However, scatter objects are matlab.graphics.chart.primitive.Scatter class, and perhaps the error message is coming from that class.

dbstop if caught error

might help track the problem down.

[Cameron McNaughton]

Having this exact same error in 2019b. Cannot run my script, or the MATLAB examples. Have used this function multiple times before installing 2019b.

works fine if just:

scatter(x,y,25); or

scatter(x,y,25,'s','filled')

but as soon as you add:

scatter(x,y,25,c)

"Warning: Error updating Scatter. Not enough input arguments."

Were you able to solve this problem?

[Walter Roberson]

What is your c? Class and size?

[Cameron McNaughton]

S = scatter(x, y,36, c', 's', 'filled')

***

Warning: Error updating Scatter.

Not enough input arguments.

***

S =

Scatter with properties:

Marker: 'square'

MarkerEdgeColor: 'none'

MarkerFaceColor: 'flat'

SizeData: 36

LineWidth: 0.5

XData: [1×33 double]

YData: [1×33 double]

ZData: [1×0 double]

CData: [1×33 double]

***

Only fails if CData passed to the function and seems to fail inside the try/catch starting at line 122 in scatter.m. Really baffled by this.

[Walter Roberson]

What is your c? Class and size?

[Cameron McNaughton]

"c" is a 1 x 33 vector of numeric values. Same size as x and y, also numeric vectors.

I belive MATLAB should automatically create a colour scale from the vector "c".

[dpb]

I've at least temporarily lost access so can't test...try reversing the order of the marker argument 's' and the color vector. The sequence in the doc makes me wonder...and I don't recall sufficiently any peculiarities have run into before regarding parsing the inputs.

Seems like I do remember it being picky about column/row vectors matching...why did you transpose c but not x,y? I'd make them all consistent on input even though the indications are it did apparently read those ok as noted I've vague recollections of issues on that score in the past.