Determining the slope between relevant 2d objects

2 views (last 30 days)
Hello all, included I have my post processed image where I've done a lot of things to it, but basically got it to this post watershed state where the edges are quite segmented.
The idea here is I want to take the slope of the objects, then be able to draw some sort of conclusion from it. For example, if I were to draw a slope along the right side set of objects, would I get a regular gradual slope, or something more like a spline curve?
Main questions:
1. How do I extract the x-y coordinates from those identified objects?
2. Is it possible to draw a 'best fit line' of sorts between the right hand objects (ignoring the ones on the left?)
Thanks!
  1 Comment
jonas
jonas on 30 Jun 2018
Edited: jonas on 30 Jun 2018
How did you identify the objects? Can you post the code or a sample code?
From the name of the file I assume you used CC=BwConncomp. The output of that function includes a field CC.PixelIdxList, where the connected pixels for each object are stored.

Sign in to comment.

Answers (1)

Image Analyst
Image Analyst on 30 Jun 2018
Why not take the points and use poly2mask() to create a solid binary image mask from them?
Then you can call bwperim() or bwboundaries() to get the boundary/outline coordinates for every adjacent pixel.
  2 Comments
Kimo Kalip
Kimo Kalip on 3 Jul 2018
Edited: Kimo Kalip on 3 Jul 2018
Lets say I wanted to grab four points:
(Smallest x value, corresponding y value)
(Corresponding x value, smallest y value)
(Corresponding x value, highest y value)
(Highest x value, corresponding y value)
First off, how do I extract those particular numbers from the matrix containing the image? Secondly, do you think that would draw a box around my object that I could take the area of, and then try to work from there?
Kinda going off of the image in:
Also, is the xi and yi values given in:
BW = poly2mask(xi,yi,m,n)
Are these arrays that I pass in those values that I want?

Sign in to comment.

Products


Release

R2017a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!