Transform a cell of arrays to a table?

How could I get B from A? Thanks!!! The cell2table command couldn't because the element in A is {[1;2;3]}, instead of {[1]},{[2]},{[3]}, which would make it a bit more complicated. I tried cell2table, cell2mat, struct2table...

A = {[1;2;3];[1;2;3];[1;2;3];[1;2;3]}

B = [1,2,3;1,2,3;1,2,3;1,2,3]

A =

4×1 cell array

    [3×1 double]
    [3×1 double]
    [3×1 double]
    [3×1 double]

B =

    1 2 3
    1 2 3
    1 2 3
    1 2 3

[Akira Agata]

Let me clarify one thing. Is B a following 4×6 char array?

>> B = ['a1','b1','c1';'a2','b2','c2';'a3','b3','c3';'a4','b4','c4']
B =
4×6 char array
  'a1b1c1'
  'a2b2c2'
  'a3b3c3'
  'a4b4c4'

[Iris Li]

I actually have the following function. Para is like A I mentioned in this question, a 4*1 cell. What I want to get is a 4*3 table.

G = findgroups(m,n);
func = @(x,y,z){[z,z.*x(:),z.*x(:).^2]\(z.*y(:))};
Para = splitapply(func,x,y,z,G);

[Iris Li]

Sorry I modified the codes in this question just now. Hopefully you'll find it more clear haha.

Answer 1

[Andrei Bobrov]

B = [A{:}]'

[Guillaume]

or

B = vertcat(A{:});

Saves on a ctranspose.

[Iris Li]

Thank you very much!