Assignment has more non-singleton rhs dimensions than non-singleton subscripts
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Muhammed AlSubhi
on 16 Apr 2018
Commented: Muhammed AlSubhi
on 16 Apr 2018
clear all clc
syms h;
v0=150:10:230;
c = [1 2 5 6 10 15 20 30 40];
th = zeros(length(v0), length(c));
tp = 0.1;
for i = 1:length(c)
for j = 1:length(v0)
t1 = (log(1+0.0509683996*c(i)*v0(j)))/c(i);
assume(h, 'real')
a = 1*10^10*c(i).^2;
b = 21962000000*c(i);
f = (-2*10^10)*c(i)*sqrt(3)-(4*10^8)*(v0(j).^2)-98100000*c(i)+36460944400;
d = (8*10^7)*(v0(j).^2)-(4*10^19)*sqrt(3)-157705560;
e = (4*10^6)*(v0(j).^2)+88400962361;
th (i,j) = vpasolve((a*h^4)+(b*h^3)+(f*h^2)+(d*h)-(e),h,[tp t1]);
t1 = 0;
end
end
2 Comments
Jan
on 16 Apr 2018
Edited: Jan
on 16 Apr 2018
Please post the complete error message, which mentions also, in which line the error occurs. This is better than letting the readers guess this important detail.
By the way, -2*10^10 is a multiplication and an expensive power operation, while -2e10 is a cheap constant. Compare the readability:
f = (-2*10^10)*c(i)*sqrt(3)-(4*10^8)*(v0(j).^2)-98100000*c(i)+36460944400;
f = -2e10 * c(i) * sqrt(3) - 4e8 * v0(j) .^ 2 - 981e5 * c(i) + 36460944400;
Accepted Answer
Birdman
on 16 Apr 2018
The output of vpasolve seems to be returning empty solutions. You can detect if the solutions are empty and assign an eps value instead but it seems all of your solutions return empty ones. That has to do something with your equation. Try this:
syms h;
v0=150:10:230;
c = [1 2 5 6 10 15 20 30 40];
th = zeros(length(v0), length(c));
tp = 0.1;
for i = 1:length(c)
for j = 1:length(v0)
t1 = (log(1+0.0509683996*c(i)*v0(j)))/c(i);
assume(h, 'real')
a = 1*10^10*c(i).^2;
b = 21962000000*c(i);
f = (-2*10^10)*c(i)*sqrt(3)-(4*10^8)*(v0(j).^2)-98100000*c(i)+36460944400;
d = (8*10^7)*(v0(j).^2)-(4*10^19)*sqrt(3)-157705560;
e = (4*10^6)*(v0(j).^2)+88400962361;
res=vpasolve((a*h^4)+(b*h^3)+(f*h^2)+(d*h)-(e),h,[tp t1]);
if isempty(res)
th (i,j) = eps;%you need to assign a value, this is a very small one,eps=2.2e-16
else
th(i,j)=res;
end
t1 = 0;
end
end
5 Comments
Birdman
on 16 Apr 2018
This piece of code differs mathematically from the initial code. Use the following code to get the results you want:
syms h;
v0=150:10:230;
c = [1 2 5 6 10 15 20 30 40];
th = zeros(length(v0), length(c));
tp = 0.1;
for i = 1:length(c)
for j = 1:length(v0)
t1 = (log(1+0.0509683996*c(i)*v0(j)))/c(i);
assume(h, 'real')
a = 1*10^10*c(i).^2;
b = 21962000000*c(i);
f = (-2*10^10)*c(i)*sqrt(3)-(4*10^8)*(v0(j).^2)-98100000*c(i)+36460944400;
d = (8*10^7)*(v0(j).^2)-(4*10^10)*sqrt(3)-157705560;
e = -(4*10^6)*(v0(j).^2)+88400962361;
res=vpasolve(a*h^4+b*h^3+f*h^2+d*h+e,h, [tp t1]);
if isempty(res)
th (i,j) = eps;%you need to assign a value, this is a very small one,eps=2.2e-16
else
th(i,j)=res;
end
t1 = 0;
end
end
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