Index exceeds error in second run

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Brinta Chowdhury
Brinta Chowdhury on 8 Apr 2018
Answered: Brinta Chowdhury on 8 Apr 2018
Hello , I am writing this code. It runs first time perfectly but second time it shows the error:
Index exceeds matrix dimensions.
Error in tr1 (line 61)
child(i)=citi_no(I)
my code is :
clc;
clear all;
close all;
P1= [5 2 1 4 3];
P2= [4 5 1 2 3];
for i=1:5
c=1;
a=find(P1==i);
if a<5 && a>1
u=P1(a-1);
v=P1(a+1);
elseif a==5
u=P1(a-1);
v=P1(1);
else
u=P1(5);
v=P1(a+1);
end
edge_table{i}(c)=u;
edge_table{i}(c+1)=v;
c=c+1;
b=find(P2==i);
if b<5 && b>1
x=P2(b-1);
y=P2(b+1);
elseif b==5
x=P2(b-1);
y=P2(1);
else
x=P2(5);
y=P2(b+1);
end
if max(ismember(edge_table{i},x))==0
edge_table{i}(c+1)=x;
c=c+1;
end
if max(ismember(edge_table{i},y))==0
edge_table{i}(c+1)=y;
end
citi_no(i)=i;
list_size(i)=length(edge_table{i});
end
idx=find(list_size==max(list_size));
chose=randi(length(idx),1);
I=idx(chose);
child(1)=citi_no(I);
for i=2:5
citi_no(I)=[];
edge_table{I}=[];
edge_table=edge_table(~cellfun('isempty',edge_table));
for j=1:numel(edge_table)
if max(ismember(edge_table{j},I))==1
d=find(edge_table{j}==I);
edge_table{j}(d)=[];
end
new_size(j)=length(edge_table{j});
end
id=find(new_size==min(new_size));
Next=randi(length(id),1);
I=id(Next);
child(i)=citi_no(I)
end
I could not find the problem.
  1 Comment
per isakson
per isakson on 8 Apr 2018
Edited: per isakson on 8 Apr 2018
My test ends with that error when the value of I is 3 and the length of citi_no is 2

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Answers (1)

Brinta Chowdhury
Brinta Chowdhury on 8 Apr 2018
Hey thanks. I found the problem just after I post the question here and fixed it already. Anyways thanks for your help.

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