Why am I getting Inf in my matrix
8 views (last 30 days)
Show older comments
paul lestingi
on 1 Apr 2018
Commented: paul lestingi
on 1 Apr 2018
I am trying to divide each position element by element, and every time the denominator = 0 I want to set the result to 1 so I don't get any infinity values (for dividing by zero). When I run the code and test with find(isinf(g)) there are a ton of values that come up as infinity. Can anyone explain why?
clc
close all
x = [0 0 0; 1 2 3;0 2 4];
y = [1 2 0; 2 4 6; 2 4 5];
for u=1:3
for v=1:3
if (x(u,v) == 0)
g(u,v) = 1;
else
g(u,v) =y(u,v)/x(u,v);
end
end
end
0 Comments
Accepted Answer
Roger Stafford
on 1 Apr 2018
Edited: Roger Stafford
on 1 Apr 2018
It is easily possible for two finite nonzero numbers to have a quotient so large that Matlab must give 'inf' as its value. For example
x = 0.01*realmax;
y = 0.0001;
q = x/y; % <-- This will yield inf for q
I suggest you make a study of the corresponding x and y values that give rise to your inf values to see what kinds of number pairs are involved.
More Answers (0)
See Also
Categories
Find more on Multidimensional Arrays in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!