# Find the maximum value and its position of a 10x10x10 matrix which meets a set of parameters.

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##### 4 Comments

Guillaume
on 29 Mar 2018

So if the max is found at (6,4,5) but the corresponding a,b,c don't fit the requirement, then what?

### Accepted Answer

Guillaume
on 29 Mar 2018

Edited: Guillaume
on 29 Mar 2018

h = 70;

c = linspace(30,60,10);

b = linspace(1,h-2,10);

a = linspace(1,14,10);

[A, B, C]=meshgrid(a,b,c);

M = D *(C.*h-2*B.*A);

%Q = ...

%Fy = ...

isinrange= Q > Fy./(1/12*(C*h^3 - 2*A.B.^3));

[maxM, idx] = max(M(isinrange));

aAtMax = A(idx);

bAtMax = B(idx);

cAtMax = C(idx);

##### 3 Comments

Stephen23
on 29 Mar 2018

Guillaume
on 29 Mar 2018

### More Answers (1)

Veera Kanmani
on 29 Mar 2018

max_value_position=max(M);

max_value=M(max(M));

##### 4 Comments

Stephen23
on 29 Mar 2018

Edited: Stephen23
on 29 Mar 2018

Given that M is a 10x10x10 array, max(M) will return a 1x10x10 array. Using that as the input to find will return as many indices as there are non-zero maximum values. If all of the values are non-zero then it will simply be a list of all linear indices of that 1x10x10 array. Lets try it with a smaller example:

>> M = rand(3,3,3);

>> find(max(M))

ans =

1

2

3

4

5

6

7

8

9

How does this list of all indices of non-zero values in the output of max help to solve the problem? How are we supposed to use these indices to "Find the maximum value and its position...", as the original question requests?

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