how to find Place on non zero values in matrix?

hey all

i need to find places of 1's in matrix A:

    A = [0,0,0,1,0,0,1,1,0;0,0,1,0,0,0,0,0,1;0,0,0,0,1,0,0,0,0]
    result = {[4,7,8];[3,9];5}

please help

Answer 1

[Stephen23]

>> A = [0,0,0,1,0,0,1,1,0;0,0,1,0,0,0,0,0,1;0,0,0,0,1,0,0,0,0];
>> [R,C] = find(A);
>> X = accumarray(R,C,[],@(v){v.'});
>> X{:}
ans =
   4   7   8
ans =
   3   9
ans = 
   5

[Tha saliem]

Thankyou so much

Answer 2

[javad ebrahimi]

HI dear Tha saliem

I hope that I have been able to understand what you mean, and the following code can help you

clc;clear;close all
 A = [0,0,0,1,0,0,1,1,0;0,0,1,0,0,0,0,0,1;0,0,0,0,1,0,0,0,0];
      B=find(A~=0)
      size=size(A)
      [Row,Col]=ind2sub(size,B)
      result={Col(Row==1),Col(Row==2),Col(Row==3)}

[Tha saliem]

Hi.. it also solves the problem. thank you for your answer.

Answer 3

[Jan]

A      = [0,0,0,1,0,0,1,1,0;0,0,1,0,0,0,0,0,1;0,0,0,0,1,0,0,0,0]
result = cellfun(@find, num2cell(A, 2), 'UniformOutput', 0)

[Tha saliem]

This is also a good approach.. Thank You