Writing function based on a vector of roots
Show older comments
In the following code, one of lines plotted is a vector of solutions to a nonlinear function (plotted against a parameter). I want to find the intersection point, but I don't know how to do it. Does anyone have any suggestion?
clc;
close all;
clear all;
lambda = 1;
Fprime = @(z) lambda.*exp(-lambda.*z);
F = @(z) 1-lambda.*exp(-lambda.*z);
F2prime = @(z) -lambda^2.*exp(-lambda.*z);
intz = @(z) (1-(lambda.*z+1).*exp(-lambda.*z))./lambda;
funz = @(z) z.*(1-F(z))+intz(z);
ph = 0.8;
pl = 0.4;
t = 0.6;
theta =1.3;
sigma = 0.6;
alpha=0.6;
epsilon = 0.1;
y = @(z,psi) (((ph-pl)/(1-t))*psi*(z.*(1-F(z))+intz(z))).^(1/theta);
u = @(z,psi) ph.*((1+epsilon).*y(z,psi)).^alpha + (1-ph).*y(z,psi).^alpha;
N2 = 200;
psigrid = linspace(.5,5,N2);
zbar2 = zeros(1,N2);
Gfun = @(z,psi) psi.*z;
rhs = @(z,psi) (sigma/.8).*(u(z,psi)-Gfun(z,psi)+(1-ph).*psi.*(1-F(z)).*z);
for k=1:N2
rhstest = @(z) rhs(z,psigrid(1,k));
Gfuntest = @(z) Gfun(z,psigrid(1,k));
zbarfun = @(z) rhstest(z) - Gfuntest(z);
zbar2(1,k) = fsolve(zbarfun,.2);
end
figure
plot(psigrid,zbar2);
hold on;
plot(psigrid,.3.*ones(1,N2));
3 Comments
Star Strider
on 1 Mar 2018
I notified the person at MathWorks who is responsible for ‘Answers’ that your post is not appearing on the main Answers page, for me either. I expect to hear back, so I’ll post back the reason when I hear about it.
It should appear, since Answers spanning about 4 hours are currently posted, and since yours is only 3 hours old, and since my Answer and this Comment are only minutes old, it should be visible.
The Answer I posted should be what you want. Your post is visible on my personal Answers page, so I can follow up on it.
John
on 1 Mar 2018
Star Strider
on 1 Mar 2018
As always, my pleasure!
I’ve not heard back yet from Rena Berman. I’ll let you know. She might post back here as well, since I included the URL to your Question in my email to her.
Accepted Answer
More Answers (0)
Categories
Find more on MATLAB in Help Center and File Exchange
Products
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!