How do I remove trailing zeros after rounding a matrix while retaining current rows/columns format?

I am trying to display a matrix that with numbers all rounded off to 1 decimal point. Currently when I round, there is a 0 that remains in the hundreths place of each number. I'd like to remove this last zero so that all my numbers only display out to the tenths place.
I have tried using the fprintf function as well as the sprintf function but I always lose the rows/column format of my matrix. Is there a way to round and then shorten an entire matrix of numbers so that there aren't any trailing zeros?
matrix = [1.34, 3.45, 2.34; 0.54, 21.34, 0.34; 11.81, 9.94, 10.02]; %3x3 matrix of data
round_matrix = round(matrix, 1); %3x3 matrix of data rounded to 1 decimal place
%My attempts thus far at removing the trailing zeros
disp_matrix = sprintf('%.1f', rounded_matrix); %This resulted in a string of all of my numbers mashed together
disp_matrix = fprintf('%.1f\n',round(Table_outnumeric)); %This resulted in all of my numbers being converted into a single column

 Accepted Answer

How about as follows,
>> disp_matrix = num2str(round_matrix, '%.1f '); disp(disp_matrix)
1.0 0.8
0.5 0.1
To be clear, though, if you want to a matrix displayed to 1 decimal place, you have no choice but to convert it to string/char type. You cannot force MATLAB to display actual numeric matrix objects to arbitrary customized precision. However, see FORMAT for the display options that you do have.

More Answers (1)

disp_matrix = sprintf('%.1f ', round_matrix)

1 Comment

This answer results in a single row of numbers:
>> matrix = rand(2,2)
matrix =
0.9572 0.8003
0.4854 0.1419
>> round_matrix = round(matrix,1)
1.0000 0.8000
0.5000 0.1000
>> disp_matrix = sprintf('%.1f ', round_matrix)
disp_matrix =
'1.0 0.5 0.8 0.1 '
I ultimately want to retain my 2x2 matrix of the rounded numbers like this:
>> round_matrix = [1.0, 0.8; 0.5, 0.1]
1.0 0.8
0.5 0.1

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Asked:

on 7 Feb 2018

Edited:

on 7 Feb 2018

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