How do you assign into a function space a variable that exists in the caller script?

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I have a an anonymous function that uses specific inputs. When I call the function from the caller script, I want to also pass a parameter vector into the function space. However, I can't seem to do this correctly.
I am trying this repeatedly using the "assigning" function, with various permutations of 'base' and 'caller," and can't seem to make it work.
  4 Comments
Steven Lord
Steven Lord on 17 Jan 2018
If you try Stephen's and Walter's advice and it still doesn't work, I recommend showing a small segment of code to illustrate concretely what you're trying to do. Your original problem description was very general, so the advice we could give also could only be general. The more detailed and specific the description of the problem we have, the more focused our suggestions can be.
Patrick Anderson
Patrick Anderson on 17 Jan 2018
Edited: Patrick Anderson on 17 Jan 2018
The "nested" suggestion turned out to be the best one, but was a little difficult to figure out from the Matlab documentation. Thank you, Stephen, for the suggestion.
The "assignin" documentation is downright ambiguous and, in my opinion, should be extensive improved.

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Accepted Answer

Walter Roberson
Walter Roberson on 17 Jan 2018
Demonstration code:
function at
junk = 123;
freedo = 222;
foo = @(junk) fprintf('%d, %d\n', alter1()+junk, alter2()+junk)*0+freedo;
foo(junk)
function r = alter1
assignin('caller', 'junk', 987);
assignin('caller', 'freedo', 111);
r = 0;
function r = alter2
assignin('caller', 'junk', 456);
assignin('caller', 'freedo', 888);
r = 0;
  1 Comment
Patrick Anderson
Patrick Anderson on 17 Jan 2018
We ended up using the "nested" suggestion. However, I appreciate this suggestion as well. I recommended the Mathworks improve their description of this commmand also.

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