Convert a vector to a binary matrix
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Utkarsh Barsaiyan
on 2 Jan 2018
Edited: Pawel Jastrzebski
on 2 Jan 2018
y = [1; 1; 2; 3; 4; 4];
I want to convert this to a matrix such that in each row the corresponding element is 1 and the rest are zero.
y = [1 0 0 0;
1 0 0 0;
0 1 0 0;
0 0 1 0;
0 0 0 1];
What is the best way to do this preferably without using loops?
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Accepted Answer
Guillaume
on 2 Jan 2018
Use sub2ind to transform row/column coordinates in linear indices and use that linear index to assign to your destination matrix:
y = [1; 1; 2; 3; 4; 4];
newy = zeros(numel(y), max(y));
newy(sub2ind(size(newy), 1:numel(y), y')) = 1
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More Answers (1)
Pawel Jastrzebski
on 2 Jan 2018
Edited: Pawel Jastrzebski
on 2 Jan 2018
With LOOP:
y = [1; 1; 2; 3; 4; 4];
nRow = length(y);
nCol = max(y);
A = zeros(nRow,nCol);
for i=1:nRow
A(i,y(i)) = 1;
end
A
WITHOUT LOOP:
y1 = [1; 1; 2; 3; 4; 4];
nRow1 = length(y1);
nCol1 = max(y1);
A1 = zeros(nRow1,nCol1);
index = (y1-1).*nRow1+(1:nRow1)';
A1(index) = 1;
A1
2 Comments
Birdman
on 2 Jan 2018
What is the best way to do this preferably without using loops?
Do not use loop.
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