MATLAB Answers


creating Lagrange interpolation w.r.t. two arrays

Asked by sermet on 25 Dec 2017
Latest activity Edited by sermet on 26 Dec 2017
time=[t1 t2 t3];
data=[y1 y2 y3];
% for specific time tt, computation of data as follows;
data(tt)=((tt-t2)*(tt-t3))/((t1-t2)*(t1-t3))*y1 + ((tt-t1)*(tt-t3))/((t2-t1)*(t2-t3))*y2 + ((tt-t1)*(tt-t2))/((t3-t1)*(t3-t2))*y3
How can I create data(tt) w.r.t. arbitrary number of time and data array?


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1 Answer

Answer by ANKUR KUMAR on 25 Dec 2017

time=[t1 t2 t3];
data=[y1 y2 y3];
tt=[tt1 tt2 tt3 tt4 tt5 tt6 tt7];
for i=1:length(tt)
data(i)=((tt(i)-t2)*(tt(i)-t3))/((t1-t2)*(t1-t3))*y1 +...
((tt(i)-t1)*(tt(i)-t3))/((t2-t1)*(t2-t3))*y2 + ((tt(i)-t1)*(tt(i)-t2))/((t3-t1)*(t3-t2))*y3;
You can even replace t1 by time(1) and so on.


t1,t2,t3 and y1,y2,y3 should be given as loop. Because their's number are variable.
Is your problem resolved?
No. Your codes are just working for above example. When t and y vectors' length are taken into consideration (they are variable, i.e, changes w.r.t. example), they should be represented as t(i), y(i) within loop.

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