please help me to solve the issue:

clear all
clc
%-----Simulation Parameters-----%
Bmax=2000000; %maximum available bandwidth for OFDMA
noise=1e-9; %fixed noise power is assumed
p_fix=0.01; %fixed transmit power is assumed
N_UE=[10 20 30 40 50];
N_SC=[60 70 80 90 100];
for it=1:2
for t= 1:length(N_UE)
     %-----Topology-----%
    Xmax=1; % x-coordinate for base station
    Ymax=1; % y-coordinate for base station
    radius=5; %coverage radius
    xsd=ones(1,N_UE(t))*Xmax;
    ysd=ones(1,N_UE(t))*Ymax;
    rrx=radius*sqrt(rand(1,N_UE(t)));
    thetarx=2*pi*rand(1,N_UE(t));
    ang=0:0.01:2*pi;
    xrx=xsd+rrx.*cos(thetarx); %random position of receivers-->x-coordinate
    yrx=ysd+rrx.*sin(thetarx); %random position of receivers-->x-coordinate
    th = 0:pi/100:2*pi;
    xunit = radius * cos(th) + Xmax;
    yunit = radius * sin(th) + Ymax;
%     figure
%     plot(xunit, yunit);
%     hold on
%     plot(ysd,xsd,'r^')
%     hold on
%     plot(yrx,xrx,'ko')
%     hold on
    %-----Subcarrier Correlation Matrix-----%
    ratio=0.1; %Td over Tb: delay spread relative to OFDM frame duration
    c=2*pi*ratio;
       for r = 1:length(N_SC)
         for j=1:N_UE(t)
            temp=[];
            for n=1:N_SC(r)
                nc=(n-1)*c;
                entry=(1+i*nc)/(1+nc^2);
                temp=[temp entry];
            end
            Rchan=toeplitz(temp);
            %autocorrelation matrix
            [E,L]=eig(Rchan);
            SQRTL=sqrt(L);
            A=E*SQRTL/sqrt(2);
            GG=randn(N_SC(r), 1)+i*randn(N_SC(r),1);
            H=A*GG;
            HH=abs(H);
%            figure
%            plot(abs(H))
%            hold on
            for k=1:N_SC(r)
                F(j,k)=HH(k);
            end
        end
       %-----Subcarrier Gain-----%
        as=4;
        bs=10;
        Lsigma=as+(bs-as)*rand(1,N_UE(t));
        Lshadow=10.^(randn(1,N_UE(t)).*(Lsigma/10));
        ae=3;
        be=5;
        Lexp=ae+(be-ae)*rand(1,N_UE(t));
        for k=1:N_SC(r)
            for j=1:N_UE(t)
                dist2(j)=sqrt((xrx(j)-xsd(j))^2+(yrx(j)-ysd(j))^2);
                G(j,k)=(F(j,k)*Lshadow(j))/dist2(j).^Lexp(j);
            end
        end
        %subcarrier allocation to users%
        siz = size(G);
        idx = sub2ind(siz, randi([1,N_UE(t)], 1, siz(2)), 1:siz(2));
        C = zeros(siz);
        C(idx) = G(idx);
        D=sum(C,2); 

% Throughput performance %
        throughput =((Bmax.*log(1+((p_fix).*C))./noise));
        overall_throughput = sum(sum(throughput));
        output(t,r)=overall_throughput;
        output_it(t,r,it)=output(t,r);
 %       figure
%         plot(overall_throughput,'b','linewidth',2);
%         legend(['No.of subcarriers=' num2str(N_SC(r))])
%         xlabel('No of users')
%         ylabel('overall_throughput')
%         axis square
%         grid on

      end
  end
  end

out = sum(output_it,3);
final = out./2;

%Group formation%
N_G=5;%No of group
B = cell(N_G,1);
sumB = cell(N_G,1);
for d=1:1:N_G
    if d==1
      e=randi([1 5],1)% select No of UE randomly  
    else
      sz=length(C(:,1));
    e=randi([1 sz],1)% select No of UE randomly   
    end
    idx=randsample(1:size(C,1),e)
    B{d} = C(idx,:)
%     C(idx,:) = [];
    [rows, columns] = size(B{d});
    % Get sum of columns and replicate vertically.
    sumB{d} = repmat(sum(B{d},1), [rows, 1]);
end

E=[sumB{1}; sumB{2};sumB{3};sumB{4};sumB{5}];

The code gets execueted. But the size of the array in the command line

E=[sumB{1}; sumB{2};sumB{3};sumB{4};sumB{5}]

command is not same as the input (50,100).Could anybody help me solve this issue.

[Stephen23]

"But the size of the array in the command line... is not same as the input (50,100)"

Why should it be? You use randsample to pick a random number of rows.

[John D'Errico]

Will you please stop asking the identical question multiple times? You asked this question twice. That is one reason you have asked now 117 questions, Almost all of them have been asked at least twice.

Answer 1

[ANKUR KUMAR]

You have used

randsample(1:size(C,1),e)

in between of the program. Just because of this, you are getting F of different dimensions.

[Prabha Kumaresan]

ok.How to solve it.

[Stephen23]

@Prabha Kumaresan: change your code.

It is your code, so surely you understand how it works.

Why do you expect other people to work through your code and figure out what it does and how it works, if you are not prepared to put in any effort yourself?

[Image Analyst]

Prabha, HERE is how to solve it, guaranteed: CLICK HERE