I am trying to make a table with the outputs of for loop!

 format long
 close all
 clear all
 clc
 xu=10;
 xl=0;
 xrpv=0;
 er=0;
 f=@(x)(5*exp(0.5*x)+10-x^3.5);
 for i=1:1:200;
    xr=(xl+xu)/2;
    fxr=f(xr);
    er=((xr-xrpv)/xr)*100;
    xrpv=xr;

    if (f(xl)*f(xr)>0)
        xl=xr;
    else
        xu=xr;
    end
    if abs(er)<10^-6
        disp(abs(er));
        break
    end

 end

table like;

i xl xr xu  fxr er
1 0   5 10   -208.596 100
2 ** *** * ***  **  **
3 ** *** ** ** ** **

Answer 1

[Brendan Gray]

If you just wish to print the output to the command window, the fprintf function is very useful for printing and formatting data.

In your code, you could do something like this:

format long
close all
clear all
clc
xu=10;
xl=0;
xrpv=0;
er=0;
f=@(x)(5*exp(0.5*x)+10-x^3.5);

fprintf('i \t\t xl \t\t xr \t\t xu \t\t fxr \t\t er\n')

for i=1:1:200;
    xr=(xl+xu)/2;
    fxr=f(xr);
    er=((xr-xrpv)/xr)*100;
    xrpv=xr;
    if (f(xl)*f(xr)>0)
        xl=xr;
    else
        xu=xr;
    end
    if abs(er)<10^-6
        disp(abs(er));
        break
    end

      fprintf('%i\t%8.3f\t%8.3f\t%8.3f\t%8.3f\t%8.3f\n', i, xl, xr, xu, fxr, er)

end

You can play around with spacing to get the headers to line up. In the format specifier, you use placeholders such as '%8.3f'. The percent starts the placeholder, the 8 specifies that I want the number to take up 8 spaces (this ensures the columns line up properly). The .3 indicates that I want three decimal places, and the f indicates that I want to use fixed point notation.

Here are the first few lines of output:

 i         xl          xr          xu          fxr         er
 1       0.000       5.000       5.000    -208.596     100.000
 2       2.500       2.500       5.000       2.746    -100.000
 3       2.500       3.750       3.750     -59.516      33.333
 4       2.500       3.125       3.125     -20.094     -20.000