v1= 81;
v2= 82;
v3= 83;
v4= 84;
n1=2000;
n2=1500;
n3=1000;
n4=500;
syms v c a
Y = solve(v+(c*n1^a)-v1,v+(c*n2^a)-v2,v+(c*n3^a)-v3,v,c,a)
Y = [Y.v Y.c Y.a]
% Check now we back substitue the values v1 should be equal to v1f
v1f=Y(1)+(Y(2)*n1^-Y(3))
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