Nested loop code to fill a 10x100 matrix

Hi all,

I'm pretty stuck on this one; I want to fill a 10x100 matrix as: A =

     [1     2   3   . . .100
     101   102 103       .
     201   202 203       .
     .               .   .
     .                 . .
     901   .   .     . . 1000]

Since I want to make use of for loops, I've made the following code:

 u=10; 
 v=100;
 A=zeros(u,v);

 for m=1:u;
     for n=1:v;
        A(m,n)= ....
    end
end

I manage to get the first row going from 1 to 100, but I can't seem to get the second row (and so on) to start with A(1,1)+m*100. I can guess that the problem is in the first loop, but I just can't seem to solve it. Anyone here who can help me getting the right code for A(m,n)=....? Or am I doing it completely wrong in the first place?

Thank you!

[James Tursa]

Do you have to use loops because this is a homework assignment?

Answer 1

[Jan]

You are almost there: All you have to do is to set the element to 100*(m-1) + n.

Sorry for solving your homework, if it is one. Note that your teacher knows this forum also. But you have shown your effort and asked clearly.

[Kjell Star]

Thank you very much, I see why I could not think of the right answer in the first place now. Hopefully this will help me in future problems.

Answer 2

[Andrei Bobrov]

out = (1:100) + (0:100:900)'

for older version of MATLAB:

out = bsxfun(@plus,1:100,(0:100:900)')

[Jan]

Note: See this example https://www.mathworks.com/matlabcentral/answers/356103-euclidean-distance-ed-calculation-in-matlab#answer_281678: The function is 10% faster with bsxfun compared to auto-expansion in R2016b. The auto-expansion is nice, but I have the impression, that the implementation is much less efficient than bsxfun.

Answer 3

[Image Analyst]

A(m,n)= (m-1)*100+n;