group an array according a condition
1 view (last 30 days)
Show older comments
Hi everyone
i have an array like this
A=
2 10 10.1 12 14 110
2 10.1 11 12 15 145
3 12 12 12 24 223
3 12 11.4 11 23 100
3 10 12 20 18 211
4 9 23 11 11 98
I want to create a new B array where i get the maximum value of each column according to the first column value
B=
2 10.1 11 12 15 145
3 12 12 20 24 223
4 9 23 11 11 98
i don´t want to use loops. is there a way to do it by using just matlab functions?
thanks in advance
0 Comments
Accepted Answer
Andrei Bobrov
on 9 Aug 2017
Edited: Andrei Bobrov
on 10 Aug 2017
B_table = varfun(@max,array2table(A),'GroupingVariables','A1')
or
B = splitapply(@(x)max(x,[],1),A,findgroups(A(:,1)));
or
g = findgroups(A(:,1)); % or >> [~,~,g] = unique(A(:,1))
[ii,jj] = ndgrid(g,1:size(A,2));
B = accumarray([ii(:),jj(:)],A(:),[],@max);
2 Comments
John BG
on 10 Aug 2017
Edited: John BG
on 10 Aug 2017
and then back to array
B=table2array(Btable)
B =
2.0000 2.0000 10.1000 11.0000 12.0000 15.0000 145.0000
3.0000 3.0000 12.0000 12.0000 20.0000 24.0000 223.0000
4.0000 1.0000 9.0000 23.0000 11.0000 11.0000 98.0000
no need for the frequencies
B(:,2)=[]
B =
2.0000 10.1000 11.0000 12.0000 15.0000 145.0000
3.0000 12.0000 12.0000 20.0000 24.0000 223.0000
4.0000 9.0000 23.0000 11.0000 11.0000 98.0000
More Answers (1)
Stephen23
on 9 Aug 2017
Edited: Stephen23
on 9 Aug 2017
A = [
2 10 10.1 12 14 110
2 10.1 11 12 15 145
3 12 12 12 24 223
3 12 11.4 11 23 100
3 10 12 20 18 211
4 9 23 11 11 98];
%
[~,~,X] = unique(A(:,1));
V = 1:size(A,1);
fun = @(r){max(A(r,:),[],1)};
C = accumarray(X,V(:),[],fun);
Z = vertcat(C{:})
produces this:
Z =
2.0000 10.1000 11.0000 12.0000 15.0000 145.0000
3.0000 12.0000 12.0000 20.0000 24.0000 223.0000
4.0000 9.0000 23.0000 11.0000 11.0000 98.0000
0 Comments
See Also
Categories
Find more on Matrices and Arrays in Help Center and File Exchange
Products
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!