Suppose I have a matrix of size(3,3).This is up-scaled by 2 making it (6,6).So there would be a number of vacant values between each element of the initial (3,3) matrix.Then how do you fill up the 0 values in addmatrixR by bicubic/liner interpolation
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prevR=magic(3)
m=1;
k1=1
addRmatrix= zeros(2*size(prevR,1),2*size(prevR,2))
for i=1:size(prevR,1);
for j=1:size(prevR,2);
addRmatrix(m,k1)= prevR(i,j);
k1=k1+2 ;
end
m=m+2;
k1=1;
end
Accepted Answer
More Answers (1)
C.J. Harris
on 17 Jul 2017
Just use interp2 on the original matrix, like so:
prevR = magic(3)
ans =
8 1 6
3 5 7
4 9 2
addRmatrix = interp2(prevR,1)
ans =
8.0000 4.5000 1.0000 3.5000 6.0000
5.5000 4.2500 3.0000 4.7500 6.5000
3.0000 4.0000 5.0000 6.0000 7.0000
3.5000 5.2500 7.0000 5.7500 4.5000
4.0000 6.5000 9.0000 5.5000 2.0000
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