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terminating the while if loop

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sermet
sermet on 14 Jul 2017
Edited: Jan on 14 Jul 2017
while abs(dE) > 1e-12
iteration=iteration+1;
E_old = E;
E = M+(ecc(1)*sin(E)); %eccentric anomaly
dE=E-E_old;
if iteration==1000
warndlg('iteration cannot be converged ', 'Error!', 'modal')
end
end
How can I modify above code to terminate the while loop when iteration exceeds 1000?

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Accepted Answer

Star Strider
Star Strider on 14 Jul 2017
Edited: Star Strider on 14 Jul 2017
I would add a break or return in your if block:
if iteration>=1000
warndlg('iteration cannot be converged ', 'Error!', 'modal')
return
end

  2 Comments

sermet
sermet on 14 Jul 2017
it doesn't terminate while loop because abs(dE) is always higher than 1e-12.
Star Strider
Star Strider on 14 Jul 2017
change the if condition to:
if (iteration>=1000) || (abs(dE) < 1e-12)
warndlg('iteration cannot be converged ', 'Error!', 'modal')
return
end
That should work as you want it to.

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More Answers (1)

Jan
Jan on 14 Jul 2017
Edited: Jan on 14 Jul 2017
limit = 1000;
iter = 0;
dE = 1;
while abs(dE) > 1e-12 && iter < limit
iter = iter + 1;
E_old = E;
E = M+(ecc(1)*sin(E)); %eccentric anomaly
dE = E-E_old;
end
if iter == limit
warndlg('iteration cannot be converged ', 'Error!', 'modal')
end

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