Use loop for indexing
2 views (last 30 days)
Show older comments
I'm trying to retriev an index from data by passing labels from 1 to 2 but the for loop is not changing?
clc;
clear all;
close all;
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
c=2;
labels =[2,1,2,1,2,1,2,1,2,2];
data =[-26.152,0.59028;2.0480,1.1151;-16.680,0.704710;8.2308,1.1567;-14.1760,-0.879840;
7.81450,0.7927;-20.220,0.992;8.921,0.822;-16.507,0.5297;-11.212,-1.6457];
colors={'r.' 'gx' 'b+' 'ys' 'md' 'cv' 'k.' 'r*' 'g*' 'b*' 'y*' 'm*' 'c*' 'k*' };
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
for i=1:c
index = find(labels == i);
if ~isempty(index)
dat=data(index,:);
plot(dat(:,1),dat(:,2),colors{i})
end
end
for i=1:c
index=find(labels == 1);
f0(index,i)=1;
end
result.data.f=f0;
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
i=2 not 1, 2
1 Comment
Geoff Hayes
on 24 Jun 2017
shawin - why do you expect i to be 1,2? You have two for loops, so when the second one iterates over 1 and 2 so it will be assigned a value of 2 when the loop completes. Try using the debugger to step through the code and see this.
Answers (1)
Jan
on 24 Jun 2017
Edited: Jan
on 24 Jun 2017
Use the auto-indentation to get clear code:
for i=1:c
index = find(labels == i);
if ~isempty(index)
dat=data(index,:);
plot(dat(:,1),dat(:,2),colors{i})
end
end
for i=1:c
index=find(labels == 1);
f0(index,i)=1;
end
Perhaps "i=2 not 1, 2 " means the second loop. Is "labels == 1" a typo and you meant "labels == i" as in the first loop?
By the way: "logical indexing" is faster:
for k = 1:c
index = (labels == k); % Without FIND
f0(index, k) = 1;
end
0 Comments
See Also
Categories
Find more on Matrix Indexing in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!